7!!! + 3!! - √100 + √36 × 22/3
³log27 + sin ( 30° ) + √100 - ⅔
nt :
seandainya aja warn nya ilang TvT
pasti udah naik ke gelar selanjutnya
Ditanya
7!!! + 3!! - √100 + √36 × 22/3
³log27 + sin ( 30° ) + √100 - ⅔
Nomor 1
Soal
7!!! + 3!! - √100 + √36 × 22/3
Hasil
49
Penyelesaian
7!!! + 3!! - √100 + √36 × 22/3
= (( 7 × 4 ) × 1 )) + ( 3 × 1 ) - √10² + √6² × 22/3
= ( 28 × 1 ) + 3 - 10 + 6 × 22/3
= 28 + 3 - 10 + 3 + 6 × 22/3
= 28 + 3 - 10 + 3 + 3 × 22
= 31 - 10 + 3 + 44
= 21 + 44
= 65
Penjelasan
( 6 × 22/3 ) = 6 Dan 3 Di ( ÷ )
Nomor 2
Soal
³log 27 + sin ( 30° ) + √100 - ⅔
Hasil
4
Penyelesaian
³log 27 + sin ( 30° ) + √100 - ⅔
= 3 × ³log 3 + ½ + √10² - ⅔
= 3 × 1 + ½ + 10 - ⅔
= 3 + ½ + 10 - ⅔
= 3 + 5 - ⅔
= 1 + 5 - 2
= 6 - 2
= 4
Penjelasan
( ½ + 10 ) = Di Bagi Terlebih Dahulu.
( 3 Dan ⅔ ) = 3nya Di Bagi 3.
⃢~ Opung~⃠⃫⃟⃤᳗᳐
7!!! + 3!! - √100 + √36 × 22/3
= ( 7.4.1 ) + ( 3.1 ) - √10² + √6² × 22/3
= 28 + 3 - 10 + 6 × 22/3
= 28 + 3 - 10 + 2 × 22
= 28 + 3 - 10 + 44
= 31 - 10 + 44
= 21 + 44
= 65
³log27 + sin(30°) + √100 - 2/3
= ³log(3³) + 1/2 + √10² - 2/3
= 3 + 1/2 + 10 - 2/3
= 1 + 5 - 2
= 6 - 2
= 4
[answer.2.content]
